// code challenge

Users from /etc/passwd

~12 min

Parse the classic colon-delimited file and extract real users.

`/etc/passwd` has one account per line, colon-delimited; field 1 is the username, field 3 the numeric UID:

``` root:x:0:0:root:/root:/bin/bash student:x:1000:1000::/home/student:/bin/bash daemon:x:1:1::/usr/sbin:/usr/sbin/nologin ```

Human accounts have **UID ≥ 1000**. Read: first line = integer N, then N passwd lines. Print the username of every human account (UID ≥ 1000), one per line, in input order.

For the sample above (N=3) the output is: ``` student ``` Hint: `parts = line.split(":")`, username = `parts[0]`, uid = `int(parts[2])`.

Language: python · Judge0

// sample tests

stdin "3\nroot:x:0:0:root:/root:/bin/bash\nstudent:x:1000:1000::/home/student:/bin/bash\ndaemon:x:1:1::/usr/sbin:/usr/sbin/nologin" → stdout "student"
stdin "2\nalice:x:1000:1000::/home/alice:/bin/bash\nbob:x:1001:1001::/home/bob:/bin/zsh" → stdout "alice\nbob"

n = int(input())
for _ in range(n):
    line = input()
    # split on ":" and print usernames with UID >= 1000